A 20 Ω resistor carries the current i = 2 + 3√2 sinωt A. Calculate the average power dissipated in the resistor in watt.

Question

G1 Physics · Accepted Answer

The DC current is 2 A and the RMS value of the AC component is 3 A. Thus Iᵣₘₛ² = 2² + 3² = 13. Therefore, P = Iᵣₘₛ²R = 13 × 20 = 260 W.