A 50 Ω resistor is connected to a voltage v = 100 + 100√2 sinωt V. Determine the average power dissipated in the resistor in watt.

Question

G1 Physics · Accepted Answer

The DC voltage is 100 V and the RMS value of the AC component is 100 V. Thus V(rms,total)² = 100² + 100² = 20000. Hence P = 20000/50 = 400 W.