A series RL circuit contains R = 10 Ω and L = 0.10 H. It is connected to v = 100 sin(100t) V. Which expression represents the steady-state current?
Options

Question

A series RL circuit contains R = 10 Ω and L = 0.10 H. It is connected to v = 100 sin(100t) V. Which expression represents the steady-state current?

G1 Physics · Accepted Answer

Here ω = 100 rad/s, so Xʟ = ωL = 10 Ω. Thus Z = √(10² + 10²) = 10√2 Ω and current amplitude I₀ = 100/(10√2) = 5√2 A. The current lags by tan⁻¹[Xʟ/R] = 45°.