A capacitor of capacitance C = 100 μF is connected to a 50 Hz AC source. Taking π = 3.14, determine Xᴄ to the nearest ohm.
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Question

A capacitor of capacitance C = 100 μF is connected to a 50 Hz AC source. Taking π = 3.14, determine Xᴄ to the nearest ohm.

G1 Physics · Accepted Answer

Xᴄ = 1/(2πfC) = 1/[2 × 3.14 × 50 × 100×10⁻⁶] ≈ 31.85 Ω, approximately 32 Ω.