A 200 V RMS source is connected across three parallel branches: R = 40 Ω, Xʟ = 50 Ω and Xᴄ = 100 Ω. Determine the magnitude of the source current.
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A 200 V RMS source is connected across three parallel branches: R = 40 Ω, Xʟ = 50 Ω and Xᴄ = 100 Ω. Determine the magnitude of the source current.

G1 Physics · Accepted Answer

Iᵣ=200/40=5 A, Iʟ=200/50=4 A and Iᴄ=200/100=2 A. The net reactive current is 2 A lagging, so source current = √(5²+2²)=√29 A.