A single-turn conducting loop of resistance 4 Ω is placed with its plane perpendicular to a magnetic field. The magnetic flux through the loop varies as Φ = 6t² - 4t + 2 Wb. Determine the magnitude of the induced current at t = 2 s.
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Question

A single-turn conducting loop of resistance 4 Ω is placed with its plane perpendicular to a magnetic field. The magnetic flux through the loop varies as Φ = 6t² - 4t + 2 Wb. Determine the magnitude of the induced current at t = 2 s.

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G1 Physics · Accepted Answer

Faraday's law gives |ε| = |dΦ/dt| = |12t − 4|. At t = 2 s, |ε| = 20 V. Hence I = |ε|/R = 20/4 = 5 A.

A single-turn conducting loop of resistance 4 Ω is placed with its plane perpendicular to a magnetic field. The magnetic flux through the loop varies as Φ = 6t² − 4t + 2 Wb. Determine the magnitude of the induced current at t = 2 s.