A 2 m conducting rod rotates about a point 0.5 m from one end with angular speed 4 rad/s in a perpendicular uniform field of 3 T. Determine the magnitude of potential difference between the two ends, in volt.
Physics · Electromagnetic Induction · Motional Electromotive Force
JEE Mains NEET

Question

A 2 m conducting rod rotates about a point 0.5 m from one end with angular speed 4 rad/s in a perpendicular uniform field of 3 T. Determine the magnitude of potential difference between the two ends, in volt.

Physics · Electromagnetic Induction · Motional Electromotive Force

G1 Physics · Accepted Answer

The two ends are at radii 0.5 m and 1.5 m on opposite sides of the axis. Their potentials relative to the axis are proportional to r²/2 with the same sign for a rigid rod. The end-to-end magnitude is (Bω/2)|1.5²−0.5²| = 6×2 = 12 V.