A 10 H inductor and a 5 Ω resistor are connected in series to a 20 V ideal battery. Determine the current, in ampere, at t=2ln2 s after closing the switch.
Physics · Electromagnetic Induction · Self Inductance
JEE Mains NEET

Question

A 10 H inductor and a 5 Ω resistor are connected in series to a 20 V ideal battery. Determine the current, in ampere, at t=2ln2 s after closing the switch.

G1 Physics · Accepted Answer

τ=L/R=2 s. Here t/τ=ln2, so I=(E/R)(1−1/2)=4×1/2=2 A.