In an ideal LC oscillator, q=Q₀cosωt. At ωt=π/4, what is the ratio of electric energy to magnetic energy?
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In an ideal LC oscillator, q=Q₀cosωt. At ωt=π/4, what is the ratio of electric energy to magnetic energy?

G1 Physics · Accepted Answer

UE/Utotal=q²/Q₀²=cos²(π/4)=1/2. The remaining half is magnetic energy, so the ratio is 1:1.