A uniformly charged non-conducting ring of radius R and total charge Q rotates with angular speed ω. Find the magnetic field at its centre.
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Question

A uniformly charged non-conducting ring of radius R and total charge Q rotates with angular speed ω. Find the magnetic field at its centre.

G1 Physics · Accepted Answer

The equivalent current is Qω/(2π). Using B=μ₀I/(2R) gives B=μ₀Qω/(4πR).