A proton enters a 0.50 T magnetic field perpendicular to the field with speed 1.0×10⁶ m/s. Calculate the radius in centimetres. Use mₚ=1.67×10⁻²⁷ kg and e=1.60×10⁻¹⁹ C.
Physics · Magnetic effect of current · motion of charge particle in magnetic field
JEE Mains NEET

Question

A proton enters a 0.50 T magnetic field perpendicular to the field with speed 1.0×10⁶ m/s. Calculate the radius in centimetres. Use mₚ=1.67×10⁻²⁷ kg and e=1.60×10⁻¹⁹ C.

G1 Physics · Accepted Answer

r=mv/(qB)=1.67×10⁻²⁷×10⁶/(1.60×10⁻¹⁹×0.50)=2.0875×10⁻² m=2.09 cm.