A prism of angle 40° produces a miniμm deviation of 30°. Which value is closest to the refractive index of the prism?
Options

Question

A prism of angle 40° produces a miniμm deviation of 30°. Which value is closest to the refractive index of the prism?

G1 Physics · Accepted Answer

At miniμm deviation, μ=sin[(A+δₘ)/2]/sin(A/2). Substituting A=40° and δₘ=30° gives μ≈1.677.