A point object in air is placed 40 cm in front of a convex spherical surface separating air from glass of refractive index 1.40. The radius of curvature of the surface is +20 cm. Using the Cartesian sign convention, determine the image distance from the pole.
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Question

A point object in air is placed 40 cm in front of a convex spherical surface separating air from glass of refractive index 1.40. The radius of curvature of the surface is +20 cm. Using the Cartesian sign convention, determine the image distance from the pole.

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G1 Physics · Accepted Answer

Use μ₂/v − μ₁/u = (μ₂−μ₁)/R. Thus 1.40/v − 1/(-40) = (1.40−1)/20. Solving gives v = -280.00 cm.