Starting from x=0, a particle goes to x=+a, then to x=-b and finally reaches x=+c, where a, b, c>0. If its average speed is five times the magnitude of its average velocity, then:
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Starting from x=0, a particle goes to x=+a, then to x=−b and finally reaches x=+c, where a,b,c>0. If its average speed is five times the magnitude of its average velocity, then:

G1 Physics · Accepted Answer

Total distance = a + (a+b) + (b+c) = 2a + 2b + c. Magnitude of displacement = c. Given average speed = 5|average velocity|, (2a+2b+c)/c = 5. Therefore 2a+2b = 4c ⇒ a+b = 2c.