A particle travels total distance D on a straight line. Its average speed is three times the magnitude of average velocity. If net displacement is positive, the total distance travelled opposite to the net displacement is:
Options

Question

A particle travels total distance D on a straight line. Its average speed is three times the magnitude of average velocity. If net displacement is positive, the total distance travelled opposite to the net displacement is:

Options

G1 Physics · Accepted Answer

Since the same total time occurs in both averages, D = 3 × displacement. Thus displacement = D/3. Let P be forward distance and N backward distance. P+N = D, P−N = D/3. Therefore 2N = 2D/3 ⇒ N = D/3.