A particle has initial velocity 2 m s⁻¹ and acceleration a = 6t - 4. Its velocity at the instant when its acceleration becomes zero is:
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A particle has initial velocity 2 m s⁻¹ and acceleration a = 6t − 4. Its velocity at the instant when its acceleration becomes zero is:

G1 Physics · Accepted Answer

a=0 gives 6t−4=0 ⇒ t=2/3 s. v(t)=2 + ∫₀→t (6τ−4)dτ = 2 + 3t² − 4t. At t=2/3, v = 2 + 4/3 − 8/3 = 2/3 m s⁻¹.