A particle has v(0)=1 m s⁻¹ and a = 12t² - 6t. At the non-zero instant at which acceleration vanishes, its velocity is:
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A particle has v(0)=1 m s⁻¹ and a = 12t² − 6t. At the non-zero instant at which acceleration vanishes, its velocity is:

G1 Physics · Accepted Answer

a = 6t(2t−1). The non-zero root is t=1/2 s. v(t)=1 + ∫₀→t(12τ²−6τ)dτ = 1 + 4t³ − 3t². At t=1/2, v = 1 + 1/2 − 3/4 = 3/4 m s⁻¹.