The velocity-position relation of a particle is v = k√(L²-x²). Its acceleration at x=L/2 is:
Options

Question

The velocity-position relation of a particle is v = k√(L²−x²). Its acceleration at x=L/2 is:

G1 Physics · Accepted Answer

Use a = v dv/dx. For v = k√(L²−x²), dv/dx = −kx/√(L²−x²). Therefore a = k√(L²−x²) × [−kx/√(L²−x²)] = −k²x. At x=L/2, a = −k²L/2.