A particle moving with constant acceleration covers 24 m during its 4th second and 36 m during its 7th second. The distance covered during its 10th second is:
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A particle moving with constant acceleration covers 24 m during its 4th second and 36 m during its 7th second. The distance covered during its 10th second is:

G1 Physics · Accepted Answer

For constant acceleration, displacement in the n-th second is sₙ = u + a(2n−1)/2. Hence s₄ = u + 7a/2 = 24, s₇ = u + 13a/2 = 36. Subtracting, 3a = 12 ⇒ a = 4 m s⁻². Then s₁₀ = u + 19a/2 = s₄ + 6a = 24 + 24 = 48 m.