Under the same constant acceleration, a train increases its speed from 10 m s⁻¹ to 20 m s⁻¹ over distance S₁ and from 20 m s⁻¹ to 30 m s⁻¹ over distance S₂. Then S₂/S₁ equals:
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Under the same constant acceleration, a train increases its speed from 10 m s⁻¹ to 20 m s⁻¹ over distance S₁ and from 20 m s⁻¹ to 30 m s⁻¹ over distance S₂. Then S₂/S₁ equals:

G1 Physics · Accepted Answer

For constant acceleration, S ∝ change in v². Therefore S₁ ∝ 20²−10² = 300, S₂ ∝ 30²−20² = 500. Hence S₂/S₁ = 500/300 = 5/3.