A particle starts from rest and moves with constant acceleration for total time T. The ratio of the distance covered during the last T/3 to that covered during the first T/3 is:
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A particle starts from rest and moves with constant acceleration for total time T. The ratio of the distance covered during the last T/3 to that covered during the first T/3 is:

G1 Physics · Accepted Answer

Starting from rest, x(t)=at²/2. Distance in first T/3: s₁ = (a/2)(T/3)² = aT²/18. Distance in last T/3: s₂ = x(T)−x(2T/3) = aT²/2 − (a/2)(4T²/9) = 5aT²/18. Hence s₂/s₁ = 5.