A particle moving with constant acceleration covers 10 m, 26 m and 42 m in three successive intervals of 2 s each. Find its speed at the midpoint in time of the second interval, in m s⁻¹.
Physics · Kinematics Part-1 (one dimension) · Motion under constant acceleration
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Question

A particle moving with constant acceleration covers 10 m, 26 m and 42 m in three successive intervals of 2 s each. Find its speed at the midpoint in time of the second interval, in m s⁻¹.

G1 Physics · Accepted Answer

Each interval has duration 2 s. The second interval is from t=2 s to t=4 s, so its midpoint is t=3 s. For constant acceleration, average velocity over an interval equals the instantaneous velocity at the midpoint of that interval. Therefore v(3) = displacement in second interval / duration = 26/2 = 13 m s⁻¹.