A balloon is moving upward with acceleration 2 m s⁻². A stone is released from it. If the balloon continues with the same acceleration, the separation between balloon and stone 2 s after release is:
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Question

A balloon is moving upward with acceleration 2 m s⁻². A stone is released from it. If the balloon continues with the same acceleration, the separation between balloon and stone 2 s after release is:

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G1 Physics · Accepted Answer

At the instant of release, balloon and stone have the same velocity. After release: acceleration of balloon = +2 m s⁻², acceleration of stone = −10 m s⁻². Relative acceleration magnitude is 2−(−10)=12 m s⁻². Initial relative velocity is zero. Separation after 2 s: relative separation = (1/2)(12)(2²) = 24 m.