Inside a lift accelerating upward at 2 m s⁻², a passenger throws a ball vertically upward with speed 12 m s⁻¹ relative to the lift. Taking g=10 m s⁻², the time after which it returns to his hand and its maximum separation from the hand are respectively:
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Question

Inside a lift accelerating upward at 2 m s⁻², a passenger throws a ball vertically upward with speed 12 m s⁻¹ relative to the lift. Taking g=10 m s⁻², the time after which it returns to his hand and its maximum separation from the hand are respectively:

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G1 Physics · Accepted Answer

Relative to the lift, the ball has downward acceleration effective gravity = g + 2 = 12 m s⁻². Time to return to the same relative level: T = 2u/effective gravity = 24/12 = 2 s. Maximum relative height: H = u²/(2effective gravity) = 144/24 = 6 m.