A juggler throws one ball vertically upward every 1 s with speed 25 m s⁻¹. Taking g=10 m s⁻², immediately after each throw, after the steady pattern has been established, the number of balls in air is:
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Question

A juggler throws one ball vertically upward every 1 s with speed 25 m s⁻¹. Taking g=10 m s⁻², immediately after each throw, after the steady pattern has been established, the number of balls in air is:

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G1 Physics · Accepted Answer

Flight time of each ball is T = 2u/g = 2(25)/10 = 5 s. With one throw every 1 s, a ball remains in air for 5 throw intervals. Therefore immediately after a throw, 5 balls are in air.