A projectile is launched with speed u. At a height y above the point of projection, its speed v is:
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A projectile is launched with speed u. At a height y above the point of projection, its speed v is:

G1 Physics · Accepted Answer

Using energy conservation between launch level and height y: u²/2 = v²/2 + gy. Therefore v² = u²−2gy. The result is independent of the launch angle.