A particle is dropped from rest. It first covers distance x₁ in time t₁ and then distance x₂ in further time t₂. If t₁/t₂ = 1/(√2-1), then:
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Question

A particle is dropped from rest. It first covers distance x₁ in time t₁ and then distance x₂ in further time t₂. If t₁/t₂ = 1/(√2-1), then:

G1 Physics · Accepted Answer

For free fall from rest, x₁=(g/2)t₁² and x₁+x₂=(g/2)(t₁+t₂)². Given t₁/t₂=1/(√2-1)=√2+1, so t₁+t₂=√2 t₁. Hence x₁+x₂=2x₁, giving x₂=x₁. Hence option A.