A particle is thrown upward from the ground. It experiences a constant resistance force that produces retardation 2 m s⁻². The ratio of time of ascent to time of descent is (g=10 m s⁻²):
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Question

A particle is thrown upward from the ground. It experiences a constant resistance force that produces retardation 2 m s⁻². The ratio of time of ascent to time of descent is (g=10 m s⁻²):

G1 Physics · Accepted Answer

During ascent the retarding acceleration is g+2=12 m s⁻², so ascent time=u/12 and H=u²/24. During descent the downward acceleration is g-2=8 m s⁻², so H=4descent time². Thus descent time=u/(4√6), and ascent time/descent time=√(2/3). Hence option B.