The ratio of the angle of minimum deviation produced by a thin prism of refractive index μ = 3/2 in air to that in a liquid of refractive index 9/7 is:
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Question

The ratio of the angle of minimum deviation produced by a thin prism of refractive index μ = 3/2 in air to that in a liquid of refractive index 9/7 is:

G1 Physics · Accepted Answer

Derived solution: Step 1: For a prism use r₁ + r₂ = A and δ = i + e - A. At minimum deviation i = e and r₁ = r₂ = A/2, so μ = sin[(A + δₘ)/2]/sin(A/2). Step 2: Substitute the values given in the question and apply the geometry/sign convention shown. Step 3: On simplification the result is 3. Therefore the correct option is B.