If T be the total time of flight of a projectile and H be the maximum height attained by it from the point of projection, then H/T will be: (u = projection velocity and θ = projection angle)
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Question

If T be the total time of flight of a projectile and H be the maximum height attained by it from the point of projection, then H/T will be: (u = projection velocity and θ = projection angle)

G1 Physics · Accepted Answer

Maximum height H = u²sin²θ/(2g) and time of flight T = 2u sinθ/g. Dividing, H/T = [u²sin²θ/(2g)]/[2u sinθ/g] = u sinθ/4. Hence option B.