A particle is projected with velocity 20 m/s at an angle of 45° with horizontal. Take g = 10 m/s². Find the maximum height (m).

Question

G1 Physics · Accepted Answer

Maximum height is H = u²sin²θ/(2g). With u = 20 m/s and θ = 45°, H = 400(1/2)/(20) = 10 m.