The equation of a projectile is y = √3x - gx²/2. At t = 0, x = 0, y = 0 and dx/dt ≠ 0. Find the speed of projection (m/s).

Question

G1 Physics · Accepted Answer

The printed equation is y = √3x - gx²/2. Compare with the standard trajectory y = x tanθ - gx²/(2u²cos²θ). Thus tanθ = √3, so θ = 60°, and u²cos²60° = 1. Hence u²/4 = 1 and u = 2 m/s.