A particle is projected with a velocity of 50 m/s at 37° with horizontal. Find the co-ordinates of the particle (w.r.t. the starting point) after 2 s. (Given, g = 10 m/s², sin 37° = 0.6 and cos 37° = 0.8)
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Question

A particle is projected with a velocity of 50 m/s at 37° with horizontal. Find the co-ordinates of the particle (w.r.t. the starting point) after 2 s. (Given, g = 10 m/s², sin 37° = 0.6 and cos 37° = 0.8)

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G1 Physics · Accepted Answer

uₓ = 50cos37° = 40 m/s and uᵧ = 50sin37° = 30 m/s. At t = 2 s: x = uₓt = 80 m and y = uᵧt - ½gt² = 60 - 20 = 40 m. Thus the coordinates are (80, 40), option B.