A projectile is thrown with a speed v at an angle θ with the vertical. Its average velocity between the instants it crosses half the maximum height is
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Question

A projectile is thrown with a speed v at an angle θ with the vertical. Its average velocity between the instants it crosses half the maximum height is

G1 Physics · Accepted Answer

The projection angle is θ with the vertical, so the constant horizontal component is uₓ = v sinθ. The projectile crosses half the maximum height once while going up and once while coming down; these two points are at the same height, so their net vertical displacement is zero. Hence the average velocity between them is purely horizontal and equals v sinθ. Therefore option A.