A ball is hit by a batsman at an angle of 37° as shown in figure. The man standing at P should run at what minimum velocity, so that he catches the ball before it strikes the ground. Assume that height of man is negligible in comparison to maximum height of projectile.

Question

G1 Physics · Accepted Answer

From the figure, u = 15 m/s, θ = 37°, and the man at P is 9 m short of the landing point B. Time of flight T = 2u sin37°/g = 2(15)(0.6)/10 = 1.8 s. To reach B before the ball lands, the man must cover 9 m in 1.8 s, so minimum speed = 9/1.8 = 5 m/s. Hence option B.