The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to blow in the direction of motion of the projectile, giving it a constant horizontal acceleration = g/2. Under the same conditions of projection, the horizontal range of the projectile will now be.
Options

Question

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to blow in the direction of motion of the projectile, giving it a constant horizontal acceleration = g/2. Under the same conditions of projection, the horizontal range of the projectile will now be.

Options

G1 Physics · Accepted Answer

The vertical motion is unchanged by the horizontal wind, so the time of flight remains T. The additional horizontal displacement due to acceleration g/2 is ½(g/2)T² = gT²/4. Since T = 2u sinθ/g, gT²/4 = u²sin²θ/g = 2H. Therefore the new range is R + 2H, option D.