Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is: (projection speed = u, angle of projection from horizontal = θ)
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Question

Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is: (projection speed = u, angle of projection from horizontal = θ)

G1 Physics · Accepted Answer

Time to the highest point is tₕ = u sinθ/g. Displacement to the highest point is x = u cosθ·tₕ and y = H = u²sin²θ/(2g). Therefore average velocity components are v̄ₓ = x/tₕ = u cosθ and v̄ᵧ = y/tₕ = u sinθ/2. Its magnitude is (u/2)√(4cos²θ + sin²θ) = (u/2)√(1 + 3cos²θ). Hence option B.