A ball is projected towards right from point A at an angle θ with vertical. The wind blows towards left along negative x-axis with acceleration g tanθ. The ball will return to point:

Question

G1 Physics · Accepted Answer

The launch angle is θ with the vertical, so uₓ = u sinθ and uᵧ = u cosθ. The flight time back to the original level is T = 2u cosθ/g. Wind gives horizontal acceleration aₓ = -g tanθ. Thus horizontal displacement is x = u sinθ·T - ½g tanθ·T² = 0. Therefore the ball returns to point A, option A.