A plane surface is inclined making an angle θ with the horizontal. From the bottom of this inclined plane, a bullet is fired with velocity v. The maximum possible range of the bullet on the inclined plane is
Select all that apply

Question

A plane surface is inclined making an angle θ with the horizontal. From the bottom of this inclined plane, a bullet is fired with velocity v. The maximum possible range of the bullet on the inclined plane is

Select all that apply

G1 Physics · Accepted Answer

For a plane inclined at θ, the range measured along the plane is R = [2v² sinα cos(α + θ)]/[g cos²θ], where α is the launch angle above the plane. Maximising with respect to α gives 2α + θ = 90°. Substituting this condition gives Rₘₐₓ = v²/[g(1 + sinθ)]. Hence option B.