A projectile is projected at an angle α (> 45°) with an initial velocity u. The time t at which its component of horizontal velocity will equal the component of vertical velocity in magnitude:
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Question

A projectile is projected at an angle α (> 45°) with an initial velocity u. The time t at which its component of horizontal velocity will equal the component of vertical velocity in magnitude:

G1 Physics · Accepted Answer

Horizontal velocity is ucosα. During ascent the vertical velocity is usinα - gt. For α > 45°, the first time the magnitudes become equal is usinα - gt = ucosα. Hence t = (u/g)(sinα - cosα). Therefore option C.

A projectile is projected at an angle α (&gt; 45°) with an initial velocity u. The time t at which its component of horizontal velocity will equal the component of vertical velocity in magnitude:

A projectile is projected at an angle α (> 45°) with an initial velocity u. The time t at which its component of horizontal velocity will equal the component of vertical velocity in magnitude: