A plane is inclined at an angle α = 30° with a respect to the horizontal. A particle is projected with a speed u = 2 ms⁻¹ from the base of the plane, making an angle θ = 15°, with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to: (Take g = 10 ms⁻²)

Question

G1 Physics · Accepted Answer

For a projectile launched at angle θ above an incline of angle α, range along the incline is R = 2u²sinθ cos(θ + α)/(g cos²α). Here u = 2 m/s, θ = 15°, α = 30° and g = 10 m/s². Thus R = [8 sin15° cos45°]/[10 cos²30°] ≈ 0.195 m ≈ 20 cm. Hence option B.