The trajectory of a projectile in a vertical plane is y = αx - βx², where α and β are constants x and y respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection θ and the maximum height attained H are respectively given by:
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Question

The trajectory of a projectile in a vertical plane is y = αx - βx², where α and β are constants x and y respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection θ and the maximum height attained H are respectively given by:

Options

G1 Physics · Accepted Answer

For y = αx - βx², comparison with the projectile equation gives tanθ = α, so θ = tan⁻¹α. The maximum height is the vertex value of the parabola: H = α²/(4β). Hence option A.