In the shown circuit the battery is ideal with emf V and the capacitor is initially uncharged. Switch S is closed at t = 0. Answer the following.

Options

• Option A

  Q = (CV/2)(1 - $e^(-2t/3RC))$

• Option B

  Q = CV(1 - $e^(-t/RC))$

• Option C

  Q = (CV/3)(1 - $e^(-3t/2RC))$

• Option D

  Q = (CV/2)$e^(-2t/3RC)$

Options

• Option A

  i = V/(2R) - [V/(6R)]$e^(-2t/3RC);$ limit = V/(2R)

• Option B

  i = V/R $e^(-t/RC);$ limit = 0

• Option C

  i = V/(2R) + [V/(6R)]$e^(-2t/3RC);$ limit = V/(2R)

• Option D

  i = V/(3R)(1 - $e^(-t/RC));$ limit = V/(3R)