A wire has resistivity ρ and cross-sectional area A. For the network shown, the equivalent resistance between P and Q is nρℓ/(√2 A). Find n.

Question

G1 Physics · Accepted Answer

Use R = ρL/A for each segment and exploit symmetry. After series-parallel reduction, the equivalent resistance is ρℓ/(√2A). Comparing with nρℓ/(√2A) gives n = 1.