A weightless rod is acted on by upward parallel forces of 2N and 4N at ends A and B respectively. The total length of the rod is AB = 3m. To keep the rod in equilibrium a force of 6N should act in the following manner:
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Question

A weightless rod is acted on by upward parallel forces of 2N and 4N at ends A and B respectively. The total length of the rod is AB = 3m. To keep the rod in equilibrium a force of 6N should act in the following manner:

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G1 Physics · Accepted Answer

For equilibrium, the resultant 6 N downward force must pass through the line of action of the two upward forces. Taking moments about A: 4×3 = 6×x, so x=2 m from A, i.e. 1 m from B. Hence D.