A ring of mass m and radius R has three particles attached as shown and rolls without slipping with centre speed v₀. What is the total kinetic energy of the complete system?

Question

G1 Physics · Accepted Answer

Because slipping is absent, ω=v₀/R. Total kinetic energy is the sum of translation and rotation of the ring plus the kinetic energies of the attached particles. Using K=½MV of CM²+½I about CMω² for the complete rigid system and the masses/positions shown gives K=6mv₀². Hence option C.