The moment of inertia of a solid cylinder about its symmetry axis is I=MR²/2. If it rolls without slipping, what is the ratio of rotational kinetic energy to translational kinetic energy?
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The moment of inertia of a solid cylinder about its symmetry axis is I=MR²/2. If it rolls without slipping, what is the ratio of rotational kinetic energy to translational kinetic energy?

G1 Physics · Accepted Answer

For rolling, v=ωR. Rotational kinetic energy = ½Iω² = ½(MR²/2)(v²/R²)=Mv²/4. Translational kinetic energy = Mv²/2. Hence K(rotational):K(translational)=1:2, so option C.