A charged particle of mass m and charge q is accelerated through a potential difference of V volt. It enters a region of uniform magnetic field B which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius :-
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Question

A charged particle of mass m and charge q is accelerated through a potential difference of V volt. It enters a region of uniform magnetic field B which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius :-

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G1 Physics · Accepted Answer

After acceleration through V, qV=½mv², so v=√(2qV/m). In B perpendicular to v, r=mv/(qB)=√(2mV/q)/B. Hence C.