Three wire loops and an observer are positioned as shown. From the observer’s point of view, current I flows anticlockwise in the middle loop, which moves towards the observer with speed v. Loops A and B are stationary. The observer would notice that:

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G1 Physics · Accepted Answer

For a moving conductor, ε=∫(v⃗×B⃗)·dℓ⃗. Combine this with Ohm’s law and Lenz’s law where required. The result is a clockwise current is induced in loop A, but a counterclockwise current is induced in loop B..