A metallic rod of length ℓ rotates in a horizontal plane with angular speed ω in a region with no magnetic field. If electron mass is m and charge magnitude is e, the emf developed along the rod is:

Question

G1 Physics · Accepted Answer

For an electron at radius r, eE=mω²r. Hence ΔV=∫₀^ℓEdr=(mω²/e)∫₀^ℓrdr=mω²ℓ²/(2e).